document.write( "Question 951858: A parking meter contained 110 coins made up of dimes and nickels. If the value of the coins was $8.60, how many dimes did the meter contain? \n" ); document.write( "
Algebra.Com's Answer #581310 by macston(5194)![]() ![]() You can put this solution on YOUR website! d=dimes; n=nickels \n" ); document.write( "n+d=110 \n" ); document.write( "d=110-n \n" ); document.write( "$0.05n+$0.10d=$8.60 Substitute for d. \n" ); document.write( "$0.05n+$0.10(110-n)=$8.60 \n" ); document.write( "$0.05n+$11.00-$0.10n=$8.60 Subtract $11.00 from each side. \n" ); document.write( "-$0.05n=-$2.40 Divide each side by -$0.05 \n" ); document.write( "n=48 There were 48 nickels \n" ); document.write( "d=110-n=110-48=62 ANSWER: There were 62 dimes. \n" ); document.write( "CHECK: \n" ); document.write( "$0.05n+$0.10d=$8.60 \n" ); document.write( "$0.05(48)+$0.10(62)=$8.60 \n" ); document.write( "$2.40+$6.20=$8.60 \n" ); document.write( "$8.60=$8.60 \n" ); document.write( " |