document.write( "Question 11118: What is the sum of the 1st 500 counting digits? That is what is the sum of 1+2+3+4+...+499+500? How about the sum of only the odd digits, 1+3+5+...+497+499? \n" ); document.write( "
Algebra.Com's Answer #5813 by askmemath(368)\"\" \"About 
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Sum of the first n counting digits = n(n+1)/2
\n" ); document.write( "So for first 500 = 500x501/2 = 250 x 501 = 125250\r
\n" ); document.write( "\n" ); document.write( "Sum of first n odd numbers = n^2
\n" ); document.write( "Check:
\n" ); document.write( "Sum of first 3 odd numbers = 1+3+5 = 9
\n" ); document.write( "n^2 = 3^2 = 9 Yay!!
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