document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951740>Question 951740</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a mom is 3 times old as his daughter. 5 years ago their sum of ages were 50.  how old is the mother </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581269 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=daughter's age; m=mom's age=3d<BR>\n" );
document.write( "If five years ago the sum of their ages were 50 years, the sum is currently 60 years. <BR>\n" );
document.write( "d+m=60 yrs Substitute for m<BR>\n" );
document.write( "d+3d=60yrs<BR>\n" );
document.write( "4d=60yrs Divide each side by 4.<BR>\n" );
document.write( "d=15yrs <BR>\n" );
document.write( "m=3d=3(15yrs)=45yrs ANSWER: The mother is 45 years old.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "(d-5yrs)+(m-5yrs)=50yrs<BR>\n" );
document.write( "(15yrs-5yrs)+(45yrs-5yrs)=50yrs<BR>\n" );
document.write( "10yrs+40yrs=50yrs<BR>\n" );
document.write( "50yrs=50yrs\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );