document.write( "Question 951733: if sally can paint a room in 6 hours while it takes steve 7 hours to paint the same room. how long would it take them to paint the room if they worked together? \n" ); document.write( "
Algebra.Com's Answer #581257 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! if sally can paint a room in 6 hours while it takes steve 7 hours to paint the \n" ); document.write( "same room. how long would it take them to paint the room if they worked \n" ); document.write( "together? \n" ); document.write( " \r\n" ); document.write( "There are two ways to do it, one with algebra and one way without algebra. \r\n" ); document.write( "I'll show both ways.\r\n" ); document.write( "\r\n" ); document.write( "WITHOUT algebra:\r\n" ); document.write( "\r\n" ); document.write( "The least common multiple of 6 hours and 7 hours is 42 hours. So in a 42 hour\r\n" ); document.write( "period working together, Sally could paint 7 rooms while Steve paints 6. So\r\n" ); document.write( "together they would have painted 13 rooms in 42 hours, so together they could\r\n" ); document.write( "paint 1 room in\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |