document.write( "Question 951714: a triangle with a perimeter of 40 meters is 2 meters longer than its wide. Deterrmine the demensions, show how you found the answer \n" ); document.write( "
Algebra.Com's Answer #581254 by macston(5194)\"\" \"About 
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W=width; L=length=W+2m; P=perimeter=2(L+W)=40m
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "40m=2(L+W) Divide each side by 2.
\n" ); document.write( "20m=L+W Substitute for L.
\n" ); document.write( "20m=W+2m+W Subtract 2m from each side.
\n" ); document.write( "18m=2W Divide each side by 2.
\n" ); document.write( "9m=W ANSWER 1: The width is 9 meters.
\n" ); document.write( "L=W+2m=9m+2m=11m ANSWER 2: The length is 11 meters
\n" ); document.write( "CHECK:
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "40m=2(11m+9m)
\n" ); document.write( "40m=2(20m)
\n" ); document.write( "40m=40m
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