document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951692>Question 951692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Near Earth’s surface, the time t required for an object to fall a distance d is given by t = 1/4d ^1/2 where t is measured in seconds and d is measured in feet. Find the time it will take an object to fall 100 feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581236 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Near Earth’s surface, the time t required for an object to fall a distance d is given by t = 1/4d ^1/2 where t is measured in seconds and d is measured in feet. Find the time it will take an object to fall 100 feet.<BR>\n" );
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document.write( "t = (1/4)sqrt(d)<BR>\n" );
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document.write( "t = (1/4)sqrt(100)<BR>\n" );
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document.write( "t = (1/4)10<BR>\n" );
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document.write( "t = 5/2<BR>\n" );
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document.write( "time = 2.5 seconds<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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