document.write( "Question 81034: Please help me solve this problem \"+2%5E-1+%2B+2%5E0+%2B+2%5E1+\"
\n" ); document.write( "I don't understand how to solve this at all. Thank-you very much for your help. 3 1/2
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Algebra.Com's Answer #58121 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
solve this problem \"+2%5E-1+%2B+2%5E0+%2B+2%5E1+\"
\n" ); document.write( "Rules to use:
\n" ); document.write( "\"highlight%28a%5E%28-m%29=1%2F%28a%5Em%29%29\"
\n" ); document.write( "In other words, anything raised to a negative power can be written as 1 over that thing to the positive power.
\n" ); document.write( "\"highlight%28a%5E0=1%29\"
\n" ); document.write( "In other words, anything to the zero power is 1.
\n" ); document.write( ":
\n" ); document.write( "\"%281%2F2%5E1%29%2B1%2B2\"
\n" ); document.write( "\"1%2F2%2B1%2B2\"
\n" ); document.write( "\"1%2F2%2B3\"
\n" ); document.write( "\"1%2F2%2B3%282%2F2%29\"
\n" ); document.write( "\"1%2F2%2B6%2F2\"
\n" ); document.write( "\"7%2F2\"
\n" ); document.write( "Happy Calculating!!!! 3 1/2
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