document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951647>Question 951647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemistry student was asked to make 100 L of 48% alcohol solution by volume by mixing 40% alcohol solution by volume and 60% alcohol solution by volume. How many litres of each must the student use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581206 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the 40% solution \"a\" and the 60% solution \"b\".\r<BR>\n" );
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document.write( "a + b = 100L Therefore, a= 100 - b\r<BR>\n" );
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document.write( ".4a + .6b = .48(100) Substitute with above information:\r<BR>\n" );
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document.write( ".4(100 - b) + .6b = .48(100) Simplify:<BR>\n" );
document.write( "40 - .4b + .6b = 48 Subtract 40, both sides, and add on the left:<BR>\n" );
document.write( ".2b = 8 Divide both sides by .2:<BR>\n" );
document.write( "b = 40 At the beginning I said let's call the 60% solution b, and now we know that b= 40, and since we said that a = 100 - b, a= 100 - 40 = 60<BR>\n" );
document.write( "Answer:<BR>\n" );
document.write( "You need 60 liters of the 40% solution, and<BR>\n" );
document.write( "you need 40 liters of the 60% solution\r<BR>\n" );
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document.write( " </SPAN>\n" );
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