document.write( "Question 951639: find the dimension of a rectangle whose perimeter is 30 m and who area is 56 mē \n" ); document.write( "
Algebra.Com's Answer #581189 by ankor@dixie-net.com(22740)\"\" \"About 
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find the dimension of a rectangle whose perimeter is 30 m and who area is 56 mē
\n" ); document.write( "2L + 2W = 30
\n" ); document.write( "simplify,divide by 2
\n" ); document.write( "L + W = 15
\n" ); document.write( "W = (15-L), use this form for substitution
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\n" ); document.write( "L * W = 56
\n" ); document.write( "Replace W with (15-L)
\n" ); document.write( "L(15-L) = 56
\n" ); document.write( "-L^2 + 15L = 56
\n" ); document.write( "change the signs, multiply by -1
\n" ); document.write( "L^2 - 15L = -56
\n" ); document.write( "L^2 - 15L + 56 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(L-7)(L-8) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "L = 7, then W = 8
\n" ); document.write( "or
\n" ); document.write( "L = 8, then W = 7
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\n" ); document.write( "Check this in the perimeter
\n" ); document.write( "2(8) + 2(7) = 30
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