document.write( "Question 951576: solve for v, where v is a real number\r
\n" ); document.write( "\n" ); document.write( "^4√2v+2 +1=3\r
\n" ); document.write( "\n" ); document.write( "Hint: There may be no solution or more than one solution,if so use commas \n" ); document.write( "

Algebra.Com's Answer #581176 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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solve for v, where v is a real number
\n" ); document.write( "^4√2v+2 +1=3
\n" ); document.write( "Assume it's
\n" ); document.write( " $\"4sqrt%282v%2B2%29+%2B+1+=+3\"$
\n" ); document.write( "subtract 1 from both sides
\n" ); document.write( " $\"4sqrt%282v%2B2%29+=+2\"$
\n" ); document.write( "raise both sides to the 4th power
\n" ); document.write( "2v + 2 = 2^4
\n" ); document.write( "2v + 2 = 16
\n" ); document.write( "2v = 16 - 2
\n" ); document.write( "2v = 14
\n" ); document.write( "v = 14/2
\n" ); document.write( "v = 7
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this on your calc, enter (2(7)+2)^(1/4) + 1 \n" ); document.write( "

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