document.write( "Question 951615: The length of a rectangle is 5 yards more than the width! If the perimeter is 42 yards, what are the length and width? \n" ); document.write( "
Algebra.Com's Answer #581162 by macston(5194)\"\" \"About 
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W=width; L=length-W+5yds; P=Perimeter=2(L+W)=42 yds
\n" ); document.write( "P=2(L+W) Substitute for L.
\n" ); document.write( "42yds=2((W+5yds)+W) Divide each side by 2.
\n" ); document.write( "21yds=2W+5yds Subtract 5yds from each side.
\n" ); document.write( "16yds=2W Divide each side by 2.
\n" ); document.write( "8yds=W ANSWER 1: The width is 8 yds.
\n" ); document.write( "L=W5 yds=8 yds+5 yds=13 yds ANSWER 2: The length is 13 yds.
\n" ); document.write( "CHECK:
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "42 yds=2(13 yds + 8 yds)
\n" ); document.write( "42 yds=2(21 yds)
\n" ); document.write( "42 yds=42 yds
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