document.write( "Question 80979This question is from textbook Algebra I
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document.write( ": use elimination to solve each system of equations\r
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document.write( "One number added to twice another number is 23. Four times the first number added to twice the other number is 38. What are the numbers? \n" );
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Algebra.Com's Answer #58116 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! X+2Y=23 \n" ); document.write( "4X+2Y=38 MULTIPLY THE FIRST EQUATION BY -1 & ADD THEM. \n" ); document.write( "-X-2Y=-23 \n" ); document.write( "-------------------- \n" ); document.write( "3X=15 \n" ); document.write( "X=15/3 \n" ); document.write( "X=5 ANSWER. \n" ); document.write( "5+2Y=23 \n" ); document.write( "2Y=23-5 \n" ); document.write( "2Y=18 \n" ); document.write( "Y=18/2 \n" ); document.write( "Y=9 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "4*5+2*9=38 \n" ); document.write( "20+18=38 \n" ); document.write( "38=38 \n" ); document.write( " \n" ); document.write( " |