document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951557>Question 951557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3times its worth. if the perimeter is 72cm. calculate the width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581155 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=3W P=perimeter=2(L+W)=72 cm<BR>\n" );
document.write( "P=2(L+W) Substitute for L<BR>\n" );
document.write( "72cm=2(3W+W) <BR>\n" );
document.write( "72cm=8W divide each side by 8<BR>\n" );
document.write( "9cm=W ANSWER The width of the rectangle is 9 cm.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "L=3W=3(9cm)=27cm<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "72cm=2(27cm+9cm)<BR>\n" );
document.write( "72cm=2(36cm)<BR>\n" );
document.write( "72cm=72cm<BR>\n" );
document.write( " </SPAN>\n" );
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