document.write( "Question 951534: find equation of normal to hyperbola x2-3y2=144 at positive end of latus rectum \n" ); document.write( "
Algebra.Com's Answer #581154 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-3y%5E2=144+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F144-3y%5E2%2F144=144+%2F144\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F144-y%5E2%2F48=1\"\r
\n" ); document.write( "\n" ); document.write( "center: (\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=144\" => \"a=sqrt%28144%29=12\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=48\" => \"b=sqrt%2848%29=6.93\"\r
\n" ); document.write( "\n" ); document.write( "then \"c%5E2=a%5E2%2Bb%5E2\" =>\"c%5E2=144%2B48=192\" => \"c=sqrt%28192%29\"
\n" ); document.write( "=> \"c=sqrt%2864%2A3%29\"=> \"c=8sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "The Latus Rectum is the line through the focus and parallel to the directrix.\r
\n" ); document.write( "\n" ); document.write( "The length of the Latus Rectum is: \r
\n" ); document.write( "\n" ); document.write( "\"2b%5E2%2Fa=%282%2A48%29%2F12=48%2F6=8\"\r
\n" ); document.write( "\n" ); document.write( "positive end of latus rectum: (\"L\",\"4\")\r
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\n" ); document.write( "\n" ); document.write( "positive end of latus rectum at Point (\"L\",\"4\"): \r
\n" ); document.write( "\n" ); document.write( "(\"c+\" ,\"b%5E2%2Fa\")=(\"8sqrt%283%29\" ,\"4\")\r
\n" ); document.write( "\n" ); document.write( "normal at (\"8sqrt%283%29\" ,\"4\")=(\"x%5B1%5D\",\"y%5B1%5D\") is:\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2x%2Fx%5B1%5D%2Bb%5E2y%2Fy%5B1%5D=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"144x%2F8sqrt%283%29%2B48y%2F4=144%2B48\"\r
\n" ); document.write( "\n" ); document.write( "\"6sqrt%283%29x%2B12y+=+192\" .......divide by 6\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%283%29x%2B2y-32+=0\"\r
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