document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951511>Question 951511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 10ft longer than twice the width. If the perimeter is 92ft, find the length and width of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581079 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=2W+10ft; P=perimeter=2(L+W)=92 ft<BR>\n" );
document.write( "P=2(L+W) <BR>\n" );
document.write( "92 ft=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "46 ft=L+W Substitute for L.<BR>\n" );
document.write( "46 ft=(2W+10 ft)+W Subtact 10 ft from each side.<BR>\n" );
document.write( "36 ft=3W Divide each side by 3.<BR>\n" );
document.write( "12 ft=W ANSWER: The width is 12 feet.<BR>\n" );
document.write( "L=2W+10ft=2(12ft)+10ft=34ft ANSWER 2: The length is 34 feet.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "92 ft=2(34 ft+12 ft)<BR>\n" );
document.write( "92 ft=2(46 ft)<BR>\n" );
document.write( "92 ft=92 ft<BR>\n" );
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