document.write( "Question 951408: If 5 is added to both the numerator and the denominator of a fraction the resut is 4/7. If 1 is subtractedfrom both the numerator and denominator the resut is 2/5. Find the fraction. \n" ); document.write( "
Algebra.Com's Answer #581004 by Fombitz(32388)\"\" \"About 
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Let the fraction be \"X%2FY\"
\n" ); document.write( "\"%28X%2B5%29%2F%28Y%2B5%29=4%2F7\"
\n" ); document.write( "\"4%28Y%2B5%29=7%28X%2B5%29\"
\n" ); document.write( "\"4Y%2B20=7X%2B35\"
\n" ); document.write( "1.\"-7X%2B4Y=15\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"%28X-1%29%2F%28Y-1%29=2%2F5\"
\n" ); document.write( "\"5%28X-1%29=2%28Y-1%29\"
\n" ); document.write( "\"5X-5=2Y-2\"
\n" ); document.write( "2.\"5X-2Y=3\"
\n" ); document.write( "Multiply eq. 2 by 2 and add to eq. 1,
\n" ); document.write( "\"-7X%2B4Y%2B10X-4Y=15%2B6\"
\n" ); document.write( "\"3X=21\"
\n" ); document.write( "\"X=7\"
\n" ); document.write( "So then,
\n" ); document.write( "\"5%287%29-2Y=3\"
\n" ); document.write( "\"35-2Y=3\"
\n" ); document.write( "\"-2Y=-32\"
\n" ); document.write( "\"Y=16\"
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