document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951393>Question 951393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580990 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region?<BR>\n" );
document.write( "L=length=15.5 ft; W=width; A=area=>170.5 sq ft<BR>\n" );
document.write( "L*W=>170.5 sq ft Divide each side by L<BR>\n" );
document.write( "W=>170.5 sq ft/L<BR>\n" );
document.write( "W=>170.5 sq ft/15.5 ft=>11 feet<BR>\n" );
document.write( "ANSWER: To cover at least 170.5 sq ft. the width must be at least 11 feet.<BR>\n" );
document.write( " </SPAN>\n" );
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