document.write( "Question 951356: Find the length of a rectangular lot with a perimeter of 130 meters if the length is 7 meters more than the width. Remember P=2L+2W
\n" );
document.write( "
\n" );
document.write( " L=36m
\n" );
document.write( " L=65m
\n" );
document.write( " L=29m
\n" );
document.write( " L=72m\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #580957 by amarjeeth123(571) ![]() You can put this solution on YOUR website! Let the width be x \n" ); document.write( "Then the length is (x+7). \n" ); document.write( "Perimeter of the rectangular lot P=2(x)+2(x+7)=2(2x+7)=4x+14 \n" ); document.write( "4x+14=130 \n" ); document.write( "4x=116 \n" ); document.write( "x=29\r \n" ); document.write( "\n" ); document.write( "Length of the rectangle=29+7=36 metres \n" ); document.write( " |