document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951213>Question 951213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=3+Ln+x-2 ALIGN=MIDDLE  ALT=\"y=3+Ln+x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > I know the vertical asymptote is x=-2 but I have no idea how to graph this. Can you please show me the steps to graphing this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580924 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I graph y=3+Ln+x-2 I know the vertical asymptote is x=-2 but I have no idea how to graph this. Can you please show me the steps to graphing this?<BR>\n" );
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document.write( "I think you meant to write the equation as y=3+ln(x-2)<BR>\n" );
document.write( "Assuming this is the right equation you want to graph, here are the steps to take:<BR>\n" );
document.write( "First, graph the basic lnx curve, which like all log curves, have an x-intercept at 1. (log(0)=1), and a asymptote: y-axis or x=0.<BR>\n" );
document.write( "Second, changing the basic curve to ln(x-2) moves the entire curve 2 units right, which places the x-intercept at 3 and the asymptote at x=2.<BR>\n" );
document.write( "Finally, adding 3, raises the curve 3 units up with no change to the asymptote at x=2 </SPAN>\n" );
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