document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951278>Question 951278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 feet more than 5 times the width. If the area is 51 square feet, find the width and the length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580923 by </B><A HREF=/tutors/aboutme.mpl?userid=sophxmai><B>sophxmai(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sophxmai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sophxmai><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 feet more than 5 times the width. If the area is 51 square feet, find the width and the length.\r<BR>\n" );
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document.write( "Area of a rectangle is the length times the width.\r<BR>\n" );
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document.write( "Let width=x<BR>\n" );
document.write( "If the length is 2 feet more than 5 times the width, then let length=5x+2<BR>\n" );
document.write( "From the question, the area=51\r<BR>\n" );
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document.write( "So,\r<BR>\n" );
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document.write( "A=wl<BR>\n" );
document.write( "A=x(5x+2)<BR>\n" );
document.write( "51=x(5x+2)\r<BR>\n" );
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document.write( "Now solve for x\r<BR>\n" );
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document.write( "51=x(5x+2)<BR>\n" );
document.write( "51=5x^2+2x<BR>\n" );
document.write( "0=5x^2+2x-51<BR>\n" );
document.write( "0=(5x+17)(x-3)<BR>\n" );
document.write( "x=-17/5, x=3\r<BR>\n" );
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document.write( "Since the width of a rectangle can't be negative, we can disregard that solution and thus x, the width=3\r<BR>\n" );
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document.write( "and if the length is 2 more than 5 times the width, the length would be 17 </SPAN>\n" );
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