document.write( "Question 951318: how to find 3 consecutive even integers such as that 3 times the sum of the last two even integers is 40 more than 5 times the first integer \n" ); document.write( "
Algebra.Com's Answer #580909 by macston(5194)![]() ![]() You can put this solution on YOUR website! n=first integer; n+2=second integer; n+2=third integer \n" ); document.write( "5n+40=3((n+2)+(n+4)) \n" ); document.write( "5n+40=6n+18 Subtract 18 from each side. \n" ); document.write( "5n+22=6n Subtract 5n from each side. \n" ); document.write( "22=n ANSWER 1: The first integer is 22. \n" ); document.write( "n+2=22+2=24 ANSWER 2: The second integer is 24. \n" ); document.write( "N+4=22+4=26 ANSWER 3: The third integer is 26. \n" ); document.write( "CHECK: \n" ); document.write( "3 times sum of last 2 is 5 times first plus 40 \n" ); document.write( "5(22)+40=3(24+26) \n" ); document.write( "110+40=3(50) \n" ); document.write( "150=150 \n" ); document.write( " |