document.write( "Question 951308: a father is now only three times as old as his son but eight years ago the father was five times as old as his son find their present ages \n" ); document.write( "
Algebra.Com's Answer #580902 by macston(5194)\"\" \"About 
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s=son's age;f=father's age=3s
\n" ); document.write( "f-8yrs=5(s-8yrs) Substitute for f.
\n" ); document.write( "3s-8yrs=5(s-8yrs)
\n" ); document.write( "3s-8yrs=5s-40yrs Add 40 yrs to each side.
\n" ); document.write( "3s+32yrs=5s Subtract 3s from each side.
\n" ); document.write( "32yrs=2s Divide each side by 2.
\n" ); document.write( "16yrs=s ANSWER 1: The son is 16 years old.
\n" ); document.write( "f=3s=3(16yrs)=48 yrs ANSWER 2: The father is 48 years old.
\n" ); document.write( "CHECK:
\n" ); document.write( "f-8=5(s-8)
\n" ); document.write( "48-8=5(16-8)
\n" ); document.write( "40=5(8)
\n" ); document.write( "40=40
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