document.write( "Question 951308: a father is now only three times as old as his son but eight years ago the father was five times as old as his son find their present ages \n" ); document.write( "
Algebra.Com's Answer #580902 by macston(5194)![]() ![]() You can put this solution on YOUR website! s=son's age;f=father's age=3s \n" ); document.write( "f-8yrs=5(s-8yrs) Substitute for f. \n" ); document.write( "3s-8yrs=5(s-8yrs) \n" ); document.write( "3s-8yrs=5s-40yrs Add 40 yrs to each side. \n" ); document.write( "3s+32yrs=5s Subtract 3s from each side. \n" ); document.write( "32yrs=2s Divide each side by 2. \n" ); document.write( "16yrs=s ANSWER 1: The son is 16 years old. \n" ); document.write( "f=3s=3(16yrs)=48 yrs ANSWER 2: The father is 48 years old. \n" ); document.write( "CHECK: \n" ); document.write( "f-8=5(s-8) \n" ); document.write( "48-8=5(16-8) \n" ); document.write( "40=5(8) \n" ); document.write( "40=40 \n" ); document.write( " |