document.write( "Question 951286: the number of dimes ihave is 10 more than twice the number of nickels the value of my coins is $9.00 how many coins do i have?
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Algebra.Com's Answer #580894 by macston(5194) You can put this solution on YOUR website! n=nickels; d=dimes=2n+10 \n" ); document.write( "$0.05n + $0.10d =$9.00 Substitute for d \n" ); document.write( "$0.05n + $0.10(2n+10)=$9.00 \n" ); document.write( "$0.05n +$0.20n + $1.00=$9.00 Subtract $1.00 from each side. \n" ); document.write( "$0.25n=$8.00 Divide each side by $0.25. \n" ); document.write( "n=32 ANSWER 1: You have 32 nickels. \n" ); document.write( "d=2n+10=2(32)+10=74 ANSWER 2: You have 74 dimes. \n" ); document.write( "CHECK \n" ); document.write( "$0.05n + $0.10d =$9.00 \n" ); document.write( "$0.05(32) + $0.10(74) =$9.00 \n" ); document.write( "$1.60+$7.40=$9.00 \n" ); document.write( "$9.00=$9.00 \n" ); document.write( " |