document.write( "Question 951279: I have 20 more nickels than i have dimes if the sum of the money i have is $8.50 how many coins of each type do I have? \n" ); document.write( "
Algebra.Com's Answer #580880 by macston(5194)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "N=no. of nickels; D=no. of dimes=N-20 \n" ); document.write( "$0.05N + $0.10D =$8.50 Substitute for D \n" ); document.write( "$0.05N+$0.10(N-20)=$8.50 \n" ); document.write( "$0.05N+$0.10N-$2.00=$8.50 Add $2.00 to each side. \n" ); document.write( "$0.15N=$10.50 Divide each side by $0.15. \n" ); document.write( "N=70 ANSWER 1:You have 70 nickels \n" ); document.write( "D=N-20=70-20=50 ANSWER 2; You have 50 dimes. \n" ); document.write( "CHECK \n" ); document.write( "$0.05N + $0.10D =$8.50 \n" ); document.write( "$0.05(70) + $0.10(50) =$8.50 \n" ); document.write( "$3.50+$5.00=$8.50 \n" ); document.write( "$8.50=$8.50 \n" ); document.write( " |