document.write( "Question 951167: Suppose that the average weekly earnings for employees in general automotive repair shops is $450, and that the standard deviation for the weekly earnings for such employees is $50. A sample of 100 such employees is selected at random. \r
\n" ); document.write( "\n" ); document.write( "Find probability that the mean of the sample is less than $445.\r
\n" ); document.write( "\n" ); document.write( "Please show how you arrived at the answer. Thanks. \n" ); document.write( "
Algebra.Com's Answer #580821 by stanbon(75887)\"\" \"About 
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Suppose that the average weekly earnings for employees in general automotive repair shops is $450, and that the standard deviation for the weekly earnings for such employees is $50. A sample of 100 such employees is selected at random.
\n" ); document.write( " Find probability that the mean of the sample is less than $445.
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\n" ); document.write( "Note: The std for sample means is s/sqrt(n)
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\n" ); document.write( "z(445) = (445-450)/[50/sqrt(100) = -1
\n" ); document.write( "P(x-bar < 445) = P(z < -1) = 0.1587
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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