document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951096>Question 951096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat takes 4 hours to travel 128km going upstream. The return trip takes 2 hours going downstream. What is the rate of the boat in still water and what is the rate of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580772 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=rate  of boat in still water, c=current<BR>\n" );
document.write( "128 km/ 4hours=r-c=32 km/hr<BR>\n" );
document.write( "128 km/2 hours=r+c=64 km/hr<BR>\n" );
document.write( "r-c=32 km/hr add c to each side<BR>\n" );
document.write( "r=32 km/hr+c<BR>\n" );
document.write( "r+c=64 km hr Substitute for r<BR>\n" );
document.write( "32 km/hr + c + c=64 km/hr Subtract 32 km/hr from each side.<BR>\n" );
document.write( "2c=32 km/hr Divide each side by 2.<BR>\n" );
document.write( "c=16 km/hr ANSWER 1: The current is 16 km/hr<BR>\n" );
document.write( "r=32 km/hr + c=32 km/hr+ 16 km/hr=48 km/hr<BR>\n" );
document.write( "ANSWER 2: The speed of the boat in still water would be 48 km/hr.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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