document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951087>Question 951087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using log rules<BR>\n" );
document.write( "Loga = 0.3<BR>\n" );
document.write( "Logb = -0.5\r<BR>\n" );
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document.write( "Solve<BR>\n" );
document.write( "log(1000a^2)\r<BR>\n" );
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document.write( "log(4throot &#8730;(b/a))\r<BR>\n" );
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document.write( "I need to evaluate while showing the use of log rules\r<BR>\n" );
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document.write( "What I have is: log(1000)+log(a^2)\r<BR>\n" );
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document.write( "wouldn't log(1000) be the same as log[Base 10] 10 so would that count as the evaluation for that part?\r<BR>\n" );
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document.write( "then log(0.3^2) = log(0.09)<BR>\n" );
document.write( "therefore, the answer log[base 10]10 + log(0.09)\r<BR>\n" );
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document.write( "and log(4th root &#8730;(b/a)) would be log(b/a)^(1/4) and therefore log(-0.5)^(1/4) - log(0.3)^(1/4)\r<BR>\n" );
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document.write( "I feeel very unsure about these answers please help\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580763 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using log rules<BR>\n" );
document.write( " Loga = 0.3<BR>\n" );
document.write( " Logb = -0.5 \r<BR>\n" );
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document.write( " Solve<BR>\n" );
document.write( " log(1000a^2)<BR>\n" );
document.write( "= log(1000) + log(a^2)<BR>\n" );
document.write( "= log(1000) + 2*log(a)<BR>\n" );
document.write( "Base 10 is the default, and 1000 = 10^3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= 3 + 2*0.3<BR>\n" );
document.write( "= 3.6<BR>\n" );
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document.write( " log(4throot &#8730;(b/a))<BR>\n" );
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document.write( "= (1/4)*log(b/a)<BR>\n" );
document.write( "= (1/4)<BR>\n" );
document.write( "= (1/4) = (1/4)*(-0.8)<BR>\n" );
document.write( "= -0.2<BR>\n" );
document.write( "====================================\r<BR>\n" );
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document.write( " I need to evaluate while showing the use of log rules <BR>\n" );
document.write( " =======================================<BR>\n" );
document.write( " What I have is: log(1000)+log(a^2) <BR>\n" );
document.write( " wouldn't log(1000) be the same as log[Base 10] 10 so would that count as the evaluation for that part? <BR>\n" );
document.write( " then log(0.3^2) = log(0.09)<BR>\n" );
document.write( " therefore, the answer log[base 10]10 + log(0.09) \r<BR>\n" );
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document.write( " and log(4th root &#8730;(b/a)) would be log(b/a)^(1/4) and therefore log(-0.5)^(1/4) - log(0.3)^(1/4) <BR>\n" );
document.write( " I feeel very unsure about these answers please help  </SPAN>\n" );
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