document.write( "Question 80940: the sum of two numbers is eighteen. the total of three times the smaller and twice the larger is forty-four. find the two numbers \n" ); document.write( "
Algebra.Com's Answer #58076 by checkley75(3666)\"\" \"About 
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X+Y=18, X=18-Y
\n" ); document.write( "3X+2Y=44 NOW SUBSTITUTE (18-Y) FOR X
\n" ); document.write( "3(18-Y)+2Y=44
\n" ); document.write( "54X-3Y+2Y=44
\n" ); document.write( "-Y=44-54
\n" ); document.write( "-Y=-10
\n" ); document.write( "Y=10 ANSWER
\n" ); document.write( "X+10=18
\n" ); document.write( "X=18-10
\n" ); document.write( "X=8 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "3*8+2*10=44
\n" ); document.write( "24+20=44
\n" ); document.write( "44=44\r
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