document.write( "Question 80940: the sum of two numbers is eighteen. the total of three times the smaller and twice the larger is forty-four. find the two numbers \n" ); document.write( "
Algebra.Com's Answer #58076 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=18, X=18-Y \n" ); document.write( "3X+2Y=44 NOW SUBSTITUTE (18-Y) FOR X \n" ); document.write( "3(18-Y)+2Y=44 \n" ); document.write( "54X-3Y+2Y=44 \n" ); document.write( "-Y=44-54 \n" ); document.write( "-Y=-10 \n" ); document.write( "Y=10 ANSWER \n" ); document.write( "X+10=18 \n" ); document.write( "X=18-10 \n" ); document.write( "X=8 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "3*8+2*10=44 \n" ); document.write( "24+20=44 \n" ); document.write( "44=44\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |