document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950859>Question 950859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the perimeter of a flag is 460 feet and the width is 70 more than the length what is the length of the flag?????????????????????????????????????????????????? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580747 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=perimeter=2(L+W); L=Length; W=width=L+70 ft<BR>\n" );
document.write( "460 ft=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "230 ft=L+W Substitute for W.<BR>\n" );
document.write( "230 ft=L+L+70 ft<BR>\n" );
document.write( "230 ft=2L+70 ft Subtract 70 ft from each side.<BR>\n" );
document.write( "160 ft=2L Divide each side by 2.<BR>\n" );
document.write( "80 ft=L ANSWER 1 The length is 80 ft.<BR>\n" );
document.write( "W=L+70 ft=80 ft+70 ft=150 ft ANSWER 2: The width is 150 ft.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "Perimeter=2(L+W)<BR>\n" );
document.write( "460 ft=2(80 ft + 150 ft)<BR>\n" );
document.write( "460 ft=2(230 ft)<BR>\n" );
document.write( "460 ft=460 ft<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );