document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950981>Question 950981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At simple interest a sum of money amounted to $2668.75 in 9 months and to $2800 in 16 months. Find the amount of money invested and the rate.\r<BR>\n" );
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document.write( "I am missing something:<BR>\n" );
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document.write( "i believe that the P and R in I=PRT are the same, but can't seem to solve the problem. Thanking you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580701 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The difference in the two amounts is simple interest on the original principal for 7 months.:$2800-2668.75=$131.25 $131.25/7 mos=$18.75/mo<BR>\n" );
document.write( "$18.75/mo*9 mo=$168.75  $2668.75-$168.75=$2500 <BR>\n" );
document.write( "ANSWER 1: The original sum invested was $2500<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "$18.75/mo*16 mo=$300 $2800-$300=$2500 <BR>\n" );
document.write( "PART 2: INTEREST RATE<BR>\n" );
document.write( "($18.75/$2500)(100 %)=0.75%/mo ANSWER 2: The interest rate is 0.75% per month.\r<BR>\n" );
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