document.write( "Question 950952: Carl, Diane, and Ed have $ 46.Carl has half as much as Diane, and Ed has $2 less than Diane. How \r
\n" ); document.write( "\n" ); document.write( "much does each have?
\n" ); document.write( "

Algebra.Com's Answer #580691 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
C=Carl's money; D=Diane's money; E=Ed's money
\n" ); document.write( "C=1/2D
\n" ); document.write( "E=D-$2
\n" ); document.write( "C+D+E=$46 Substitute for C and E
\n" ); document.write( "(1/2D)+D+(D-$2)=$46
\n" ); document.write( "2.5D-$2=$46 Add $2 to each side.
\n" ); document.write( "2.5D=$48 Divide each side by 2.5
\n" ); document.write( "D=$19.20 ANSWER 1: Diane has $19.20.
\n" ); document.write( "C=1/2D=1/2($19.20)=$9.60 ANSWER 2: Carl has $9.60.
\n" ); document.write( "E=D-$2=$19.20-$2=$17.20 ANSWER 3: Ed has $17.20.
\n" ); document.write( "CHECK:
\n" ); document.write( "C+D+E=$46
\n" ); document.write( "$9.60+$19.20+$17.20=$46
\n" ); document.write( "$46=$46
\n" ); document.write( "
\n" );