document.write( "Question 950921: sue had $10000 to invest. she invested part of it in a term deposit paying 4% per annum and the remainder in bonds paying 5% per annum. if the total interest she earned was $440, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #580682 by macston(5194)![]() ![]() You can put this solution on YOUR website! x=amount invested at 4%; y=amount invested at 5% \n" ); document.write( "x+y=$10000 \n" ); document.write( "x-$10000-y \n" ); document.write( "0.04x+0.05y=$440 Substitute for x \n" ); document.write( "0.04($10000-y)+0.05y=$440 \n" ); document.write( "$400-0.04y+0.05y=$440 Subtract $400 from each side. \n" ); document.write( "0.01y=$40 Divide each side by 0.01. \n" ); document.write( "y=$4000 ANSWER 1: $4000 was invested at 5%. \n" ); document.write( "x=$10000-$4000=$6000 ANSWER 2: $6000 was invested at 4%. \n" ); document.write( "CHECK: \n" ); document.write( "0.04x+0.05y=$440 \n" ); document.write( "0.04($6000)+0.05($4000)=$440 \n" ); document.write( "$240+$200=$440 \n" ); document.write( "$440=$440\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |