document.write( "Question 950921: sue had $10000 to invest. she invested part of it in a term deposit paying 4% per annum and the remainder in bonds paying 5% per annum. if the total interest she earned was $440, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #580682 by macston(5194)\"\" \"About 
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x=amount invested at 4%; y=amount invested at 5%
\n" ); document.write( "x+y=$10000
\n" ); document.write( "x-$10000-y
\n" ); document.write( "0.04x+0.05y=$440 Substitute for x
\n" ); document.write( "0.04($10000-y)+0.05y=$440
\n" ); document.write( "$400-0.04y+0.05y=$440 Subtract $400 from each side.
\n" ); document.write( "0.01y=$40 Divide each side by 0.01.
\n" ); document.write( "y=$4000 ANSWER 1: $4000 was invested at 5%.
\n" ); document.write( "x=$10000-$4000=$6000 ANSWER 2: $6000 was invested at 4%.
\n" ); document.write( "CHECK:
\n" ); document.write( "0.04x+0.05y=$440
\n" ); document.write( "0.04($6000)+0.05($4000)=$440
\n" ); document.write( "$240+$200=$440
\n" ); document.write( "$440=$440\r
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