document.write( "Question 950915: If a rectangle has a perimeter of 65 feet and the length is four times as long as the width. How long is the length and width? \n" ); document.write( "
Algebra.Com's Answer #580670 by macston(5194)\"\" \"About 
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W=width; L=length=4W; P=perimeter=65 inches
\n" ); document.write( "P=2(L+W) Substitute for L.
\n" ); document.write( "65 ft=2(4W+W)
\n" ); document.write( "65 ft=8W+2W
\n" ); document.write( "65 ft=10W Divide each side by 10
\n" ); document.write( "6.5 ft=W ANSWER 1: Width is 6.5 feet.
\n" ); document.write( "L=4W=4(6.5 ft)=26 feet ANSWER 2: Length is 26 feet.
\n" ); document.write( "CHECK
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "65 ft=2(26ft+6.5ft)
\n" ); document.write( "65 ft=2(32.5 ft)
\n" ); document.write( "65 ft=65 ft
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