document.write( "Question 950190: the area of a rectangle is 51 square meters. the length is 2 meters longer than the width. what is the length and width of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #580618 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"A=L%2AW\"$
\n" ); document.write( " $\"L%2AW=51\"$
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\n" ); document.write( " $\"L=2%2BW\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"%282%2BW%29W=51\"$
\n" ); document.write( " $\"W%5E2%2B2W=51\"$
\n" ); document.write( " $\"W%5E2%2B2W%2B1=51%2B1\"$
\n" ); document.write( " $\"%28W%2B1%29%5E2=52\"$
\n" ); document.write( " $\"W%2B1=0+%2B-+sqrt%2852%29\"$
\n" ); document.write( " $\"W=-1+%2B-+2sqrt%2813%29\"$
\n" ); document.write( "Only use the positive result,
\n" ); document.write( " $\"W=-1%2B2sqrt%2813%29\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"L=2-1+%2B+2sqrt%2813%29\"$
\n" ); document.write( " $\"L=1+%2B+2sqrt%2813%29\"$
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