document.write( "Question 950738: solve for x.
\n" ); document.write( "logx+log(x+1)=log(x powered by 2+2) \n" ); document.write( "
Algebra.Com's Answer #580582 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%29%2Blog%28x%2B1%29=log%28x%5E2%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%28x%2B1%29%29=log%28x%5E2%2B2%29\"...since log same, then\r
\n" ); document.write( "\n" ); document.write( "\"x%28x%2B1%29=x%5E2%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28x%5E2%29%2Bx=cross%28x%5E2%29%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2\"\r
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