document.write( "Question 950751: A rectangle is 5cm longer than double its width. Its area is 75cm^2. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #580580 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
For a rectangle,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "\"L%2AW=75\"
\n" ); document.write( "\"%28W%2B5%29W=75\"
\n" ); document.write( "\"W%5E2%2B5W=75\"
\n" ); document.write( "\"W%5E2%2B5W%2B%285%2F2%29%5E2=75%2B%285%2F2%29%5E2\"
\n" ); document.write( "\"%28W%2B5%2F2%29%5E2=300%2F4%2B25%2F4\"
\n" ); document.write( "\"%28W%2B5%2F2%29%5E2=325%2F4\"
\n" ); document.write( "\"W%2B5%2F2=0+%2B-+sqrt%28325%29%2F2\"
\n" ); document.write( "\"W=-5%2F2%2B-+%285%2F2%29sqrt%2813%29\"
\n" ); document.write( "Only the positive solution makes sense here,
\n" ); document.write( "\"W=-5%2F2%2B%285%2F2%29sqrt%2813%29\"
\n" ); document.write( "So then,
\n" ); document.write( "\"L=5-5%2F2+%2B+%285%2F2%29sqrt%2813%29\"
\n" ); document.write( "\"L=5%2F2+%2B+%285%2F2%29sqrt%2813%29\"
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