document.write( "Question 950730: solve the equation and only give the exact answer. (no decimals)\r
\n" ); document.write( "\n" ); document.write( "log(3x)+log(x-2)=log(x-4)
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Algebra.Com's Answer #580572 by erica65404(394)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%283x%29%29%2Blog%28%28x-2%29%29=log%28%28x-4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "first use the addition of logs rule [loga + logb is equivalent to log(a*b)]\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%283x%28x-2%29%29%29=log%28%28x-4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "logs on each side end up cancelling themselves out as long as everything has a log of the same base. \r
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\n" ); document.write( "\n" ); document.write( "\"3x%28x-2%29=x-4\"
\n" ); document.write( "\"3x%5E2-6x=x-4\"
\n" ); document.write( "\"3x%5E2-7x%2B4=0\"
\n" ); document.write( "\"%283x-4%29%28x-1%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x-4=0\"
\n" ); document.write( "\"x=4%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=0\"
\n" ); document.write( "\"x=1\"\r
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\n" ); document.write( "\n" ); document.write( "The answer is x = 1 and 4/3.
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