document.write( "Question 950715: If an object is projected vertically upward from ground level with an initial velocity of 280 ft/sec, then its distance s above the ground after t seconds is given by
\n" ); document.write( "s = −14t2 + 280t.
\n" ); document.write( " For what values of t will the object be more than 1050 feet above the ground?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "______ < t < ______
\n" ); document.write( "

Algebra.Com's Answer #580565 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"s+=+-14t%5E2+%2B+280t\"
\n" ); document.write( "For what values of \"t\" will the object be more than \"1050+\"feet above the ground?\r
\n" ); document.write( "\n" ); document.write( "\"1050+%3E+-14t%5E2+%2B+280t\"\r
\n" ); document.write( "\n" ); document.write( "\"14t%5E2-280t+%2B1050+%3E+0\"..............simplify, both sides divide by \"14\"\r
\n" ); document.write( "\n" ); document.write( "\"t%5E2-20t+%2B75+%3E+0\"......factor completely\r
\n" ); document.write( "\n" ); document.write( "\"t%5E2-15t+-5t%2B75+%3E+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28t%5E2-15t%29+-%285t-75%29+%3E+0\"\r
\n" ); document.write( "\n" ); document.write( "\"t%28t-15%29+-5%28t-15%29+%3E+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28t-5%29+%28t-15%29%3E=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:
\n" ); document.write( "\"%28t-5%29%3E=0\"=>\"t%3E=5\"\r
\n" ); document.write( "\n" ); document.write( "\"%28t-15%29%3E=0\"=>\"t%3E=15\"\r
\n" ); document.write( "\n" ); document.write( "combined:\r
\n" ); document.write( "\n" ); document.write( "\"5%3Cx%3C15\"
\n" ); document.write( "
\n" ); document.write( "
\n" );