document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950678>Question 950678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Father is 30 yeras older than his son however he will be only thrice as old as the after 5 years what is father's present age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580541 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S=son's age; F=father's age=S+30<BR>\n" );
document.write( "F+5=3(S+5) Substitute for F.<BR>\n" );
document.write( "(S+30)+5=3S+15 Subtract S from each side.<BR>\n" );
document.write( "35=2S+15 Subtract 15 from each side.<BR>\n" );
document.write( "20=2S Divide each side by 2.<BR>\n" );
document.write( "10=S ANSWER 1: The son is 10 years old.<BR>\n" );
document.write( "F=S+30=10+30=40 ANSWER 2: The father is 40 years old.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "F+5=3(S+5)<BR>\n" );
document.write( "40+5=3(10+5)<BR>\n" );
document.write( "45=3(15)<BR>\n" );
document.write( "45=45  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );