document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950667>Question 950667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sir please this is my last question help me to solve.<BR>\n" );
document.write( "Yeboah is 37 times as old as Aseidu.<BR>\n" );
document.write( "in 16years time yeboah would be twice as old as Aseidu.<BR>\n" );
document.write( "find their ages.<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580536 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> yeboah is 37 times as old as asseidu.\r<BR>\n" );
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document.write( "let a = age of yeboah.<BR>\n" );
document.write( "let b = age of asseidu.\r<BR>\n" );
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document.write( "equation becomes a = 37 * b\r<BR>\n" );
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document.write( "in 16 years yeboah will be twice as old as asseidu.\r<BR>\n" );
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document.write( "equation becomes (a + 16) = 2 * (b + 16)\r<BR>\n" );
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document.write( "find their ages.\r<BR>\n" );
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document.write( "you have two equations that need to be solved simultaneously.\r<BR>\n" );
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document.write( "they are:\r<BR>\n" );
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document.write( "a = 37 * b<BR>\n" );
document.write( "(a + 16) = 2 * (b + 16)\r<BR>\n" );
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document.write( "replace a in the second equation with 37 * b.\r<BR>\n" );
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document.write( "your second equation of (a + 16) = 2 * (b + 16) becomes:\r<BR>\n" );
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document.write( "(37 * b + 16) = 2 * (b + 16)\r<BR>\n" );
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document.write( "simplify to get\r<BR>\n" );
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document.write( "37 * b + 16 = 2 * b + 32\r<BR>\n" );
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document.write( "subtract 16 from both sides of the equation and subtract 2 * b from both sides of the equation to get:\r<BR>\n" );
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document.write( "37 * b - 2 * b = 32 - 16\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "35 * b = 16\r<BR>\n" );
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document.write( "divide both sides of the equation by 34 to get:\r<BR>\n" );
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document.write( "b = 16 / 35 = .4571428571\r<BR>\n" );
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document.write( "since a = 37 * b, then a = 16.91428571\r<BR>\n" );
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document.write( "in 16 years, a will be equal to 16.91428571 + 16 = 32.91428571\r<BR>\n" );
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document.write( "in 16 years, b will be equal to .4571428571 + 16 = 16.4571428571.\r<BR>\n" );
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document.write( "in 16 years a will be 2 * b.\r<BR>\n" );
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document.write( "this becomes 32.91428571 = 2 * 16.4571428571.\r<BR>\n" );
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document.write( "2 * 16.4571428571 is equal to 32.91428571.\r<BR>\n" );
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document.write( "this confirms the solution is correct.\r<BR>\n" );
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document.write( "assuming the problem was stated correctly.\r<BR>\n" );
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document.write( "yeboah is 16.91428571 years old today.<BR>\n" );
document.write( "asseidu is .4571428571 years old today.<BR>\n" );
document.write( "16.91428571 / .4571428571 = 37<BR>\n" );
document.write( "yeboah is 37 times as old as asseidu today.\r<BR>\n" );
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document.write( "yeboah is 32.91428571 years old in 16 years.<BR>\n" );
document.write( "asseidu is 16.45714286 years old in 16 years.<BR>\n" );
document.write( "32.91428571 / 16.45714286 = 2<BR>\n" );
document.write( "yeboah is 2 times as old as asseidu in 16 years.\r<BR>\n" );
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document.write( "strange numbers, but that's the way it comes out, assuming the original problem is stated as given.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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