document.write( "Question 950596: Solve for ordered pair
\n" ); document.write( "2x + y = 10
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Algebra.Com's Answer #580513 by Edwin McCravy(20056) $\"\"$ $\"About$

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document.write( "2x + y = 10\r\n" );
document.write( "3x - y = 11\r\n" );
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document.write( "Solve the first for y\r\n" );
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document.write( "y = 10 - 2x\r\n" );
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document.write( "Substitute (10 - 2x) for y in the second equation:\r\n" );
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document.write( "3x - y = 11\r\n" );
document.write( "3x - (10 - 2x) = 11   <-- distribute the \r\n" );
document.write( "3x - 5 + x = 11\r\n" );
document.write( "4x - 5 = 11\r\n" );
document.write( "4x = 16\r\n" );
document.write( " x = 4\r\n" );
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document.write( "Substitute (4) for x in\r\n" );
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document.write( "y = 10 - 2x\r\n" );
document.write( "y = 10 - 2(4)\r\n" );
document.write( "y = 10 - 8\r\n" );
document.write( "y = 2\r\n" );
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document.write( "Answer:  The two lines cross at (x,y) = (4,2)\r\n" );
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document.write( "Edwin

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