document.write( "Question 950603: Write the equation of a line perpendicular to the given line but passing through the given point.\r
\n" ); document.write( "\n" ); document.write( "y=2x-1 passing through the ordered pair (2, -2)\r
\n" ); document.write( "\n" ); document.write( "This is what I came up with
\n" ); document.write( "Again I will use the point slope form
\n" ); document.write( "y-y1= m(x-x1) and the point (2, -2)
\n" ); document.write( "First substitute the slope and my ordered pair
\n" ); document.write( "y-(-2)= -1/2 (x-2)
\n" ); document.write( "Becomes
\n" ); document.write( "y + 2= -x/2 + 2/2
\n" ); document.write( "Add -2 to both sides of the equation
\n" ); document.write( "y= -1/2x -1 which is the equation for the perpendicular line
\n" ); document.write( "This line will rise as you move left to right on the graph. The y-intercept is 1 above the origin and the x-intercept is 2 to the left of the origin. \r
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\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #580495 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
You have some details wrong, like y-intercept, but your equation is correct.
\n" ); document.write( "y=2x-1 passing through the ordered pair (2, -2)
\n" ); document.write( "The slope of the perpendicular line is the negative reciprocal, so m=-1/2, x=2, y=-2
\n" ); document.write( "Using slope-intercept form to check:
\n" ); document.write( "y=mx+b
\n" ); document.write( "-2=-(1/2)2+b
\n" ); document.write( "-2=-1 +b
\n" ); document.write( "-1=b
\n" ); document.write( "Final equation:y=-(1/2)x-1
\n" ); document.write( "Slope is -1/2, negative slope drops from left to right.
\n" ); document.write( "Y-intercept is b, so y=intercept at (0,-1), one unit below the origin.
\n" ); document.write( "X-intercept is at (-2,0)
\n" ); document.write( "\"+graph%28+800%2C+800%2C+-10%2C+10%2C+-10%2C+10%2C+-%281%2F2%29x-1%29+\"
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