document.write( "Question 950545: A train leaves Orlando at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 32 mph faster than the first. If the second train overtakes the first at 7:00 PM, what is the speed of each of the two trains?
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Algebra.Com's Answer #580456 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = the speed in mi/hr of the 1st train
\n" ); document.write( "\"+s+%2B+32+\" = the speed in mi/hr of the 2nd train
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\n" ); document.write( "From 1 PM to 3 PM is \"+2+\" hrs
\n" ); document.write( "The 1st train's head start is:
\n" ); document.write( "\"+d%5B1%5D+=+s%2A2+\"
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\n" ); document.write( "Start a stopwatch when the 2nd train leaves
\n" ); document.write( "at 3 PM and stop the watch at 7 PM
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\n" ); document.write( "Let \"+d+\" = the distance the 2nd train travels
\n" ); document.write( "from 3 PM to 7 PM
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\n" ); document.write( "Equation for the 1st train:
\n" ); document.write( "(1) \"+d+-+d%5B1%5D+=+s%2A4+\"
\n" ); document.write( "Equation for the 2nd train:
\n" ); document.write( "(2) \"+d+=+%28+s%2B32+%29%2A4+\"
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\n" ); document.write( "(1) \"+d+-+2s+=+4s+\"
\n" ); document.write( "(1) \"+d+=+6s+\"
\n" ); document.write( "Plug this result into (2)
\n" ); document.write( "(2) \"+6s+=+%28+s+%2B+32+%29%2A4+\"
\n" ); document.write( "(2) \"+6s+=+4s+%2B+128+\"
\n" ); document.write( "(2) \"+2s+=+128+\"
\n" ); document.write( "(2) \"+s+=+64+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+%2B+32+=+96+\"
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\n" ); document.write( "The speed of the 1st train is 64 mi/hr
\n" ); document.write( "The speed of the 2nd train is 96 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+6s+\"
\n" ); document.write( "(1) \"+d+=+6%2A64+\"
\n" ); document.write( "(1) \"+d+=+384+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+%28+s%2B32+%29%2A4+\"
\n" ); document.write( "(2) \"+d+=+96%2A4+\"
\n" ); document.write( "(2) \"+d+=+384+\"
\n" ); document.write( "OK
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