document.write( "Question 950521: Two investments totaling $17,500 produce an annual income of $775. One investment yields 2% per year, while the other yields 7% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #580436 by macston(5194)\"\" \"About 
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T=invested at 2%; S=invested at 7%
\n" ); document.write( "S+T=$17500
\n" ); document.write( "S=17500-T
\n" ); document.write( "0.02T+0.07S=$775 Substitute for S
\n" ); document.write( "0.02T+0.07($17500-T)=$775
\n" ); document.write( "0.02T+1225-0.07T=$775 Subtract $775 from each side.
\n" ); document.write( "-0.05T+$450=0 Add 0.05T to each side.
\n" ); document.write( "$450=0.05T Divide each side by 0.05
\n" ); document.write( "$9000=T ANSWER 1: $9000 was invested at 2%
\n" ); document.write( "S=$17500-T=$17500-$9000=$8500 ANSWER 2:$8500 was invested at 7%.
\n" ); document.write( "CHECK
\n" ); document.write( "0.02T+0.07S=$775
\n" ); document.write( "0.02($9000)+0.07($8500)=$775
\n" ); document.write( "$180+$595=$775
\n" ); document.write( "$775=$775
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