document.write( "Question 950521: Two investments totaling $17,500 produce an annual income of $775. One investment yields 2% per year, while the other yields 7% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #580436 by macston(5194)![]() ![]() You can put this solution on YOUR website! T=invested at 2%; S=invested at 7% \n" ); document.write( "S+T=$17500 \n" ); document.write( "S=17500-T \n" ); document.write( "0.02T+0.07S=$775 Substitute for S \n" ); document.write( "0.02T+0.07($17500-T)=$775 \n" ); document.write( "0.02T+1225-0.07T=$775 Subtract $775 from each side. \n" ); document.write( "-0.05T+$450=0 Add 0.05T to each side. \n" ); document.write( "$450=0.05T Divide each side by 0.05 \n" ); document.write( "$9000=T ANSWER 1: $9000 was invested at 2% \n" ); document.write( "S=$17500-T=$17500-$9000=$8500 ANSWER 2:$8500 was invested at 7%. \n" ); document.write( "CHECK \n" ); document.write( "0.02T+0.07S=$775 \n" ); document.write( "0.02($9000)+0.07($8500)=$775 \n" ); document.write( "$180+$595=$775 \n" ); document.write( "$775=$775 \n" ); document.write( " \n" ); document.write( " |