document.write( "Question 950471: Carolyn left the study group traveling 6 mph. Then, 3 hours later, Alicia left traveling the same direction at 15 mph. How long until Alicia catches up with Carolyn? How many hours? \n" ); document.write( "
Algebra.Com's Answer #580434 by Cody959(5)\"\" \"About 
You can put this solution on YOUR website!
Okay in order for us to solve this problem we need to know a fundamental physic's equation:\r
\n" ); document.write( "\n" ); document.write( "\"s=%28d%2Ft%29\" \r
\n" ); document.write( "\n" ); document.write( "This is equation:(*1)\r
\n" ); document.write( "\n" ); document.write( "Where:
\n" ); document.write( "s=speed
\n" ); document.write( "d=distance
\n" ); document.write( "t=time\r
\n" ); document.write( "\n" ); document.write( "With this equation and using simple algebraic manipulation we can find the distance that Carolyn has traveled; using her speed and the amount of time that has passed. \r
\n" ); document.write( "\n" ); document.write( "\"d=s%2At\"\r
\n" ); document.write( "\n" ); document.write( "Knowing how fast Alicia is traveling and how far Carolyn has traveled we can again use simple algebraic manipulation of equation (*1) to find the time Alicia catches Carolyn.\r
\n" ); document.write( "\n" ); document.write( "\"t=d%2Fs\"\r
\n" ); document.write( "\n" ); document.write( "Fun Fact: Equation (*1) is a fundamental idea in calculus and Newtonian physics. Velocity (speed with direction) is defined as:\r
\n" ); document.write( "\n" ); document.write( "\"V=%28ds%29%2F%28dt%29\"\r
\n" ); document.write( "\n" ); document.write( "This is known as a differential equation.
\n" ); document.write( "Where ds is defined as the change in position [or displacement]
\n" ); document.write( "And dt is defined as the amount of time that passes.\r
\n" ); document.write( "\n" ); document.write( "Hence you are doing calculus right now! :p
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