document.write( "Question 950471: Carolyn left the study group traveling 6 mph. Then, 3 hours later, Alicia left traveling the same direction at 15 mph. How long until Alicia catches up with Carolyn? How many hours? \n" ); document.write( "
Algebra.Com's Answer #580434 by Cody959(5)![]() ![]() ![]() You can put this solution on YOUR website! Okay in order for us to solve this problem we need to know a fundamental physic's equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is equation:(*1)\r \n" ); document.write( "\n" ); document.write( "Where: \n" ); document.write( "s=speed \n" ); document.write( "d=distance \n" ); document.write( "t=time\r \n" ); document.write( "\n" ); document.write( "With this equation and using simple algebraic manipulation we can find the distance that Carolyn has traveled; using her speed and the amount of time that has passed. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Knowing how fast Alicia is traveling and how far Carolyn has traveled we can again use simple algebraic manipulation of equation (*1) to find the time Alicia catches Carolyn.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Fun Fact: Equation (*1) is a fundamental idea in calculus and Newtonian physics. Velocity (speed with direction) is defined as:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is known as a differential equation. \n" ); document.write( "Where ds is defined as the change in position [or displacement] \n" ); document.write( "And dt is defined as the amount of time that passes.\r \n" ); document.write( "\n" ); document.write( "Hence you are doing calculus right now! :p \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |