document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950461>Question 950461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ten yrs ago, a father was three times as old as his son. If he is only twice as old as his son, find their present ages? <BR>\n" );
document.write( "Hope u help me answer this question? Tnx. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580402 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=father's age; S=son's age<BR>\n" );
document.write( "F=2S<BR>\n" );
document.write( "F-10=3(S-10) Substitute for F.<BR>\n" );
document.write( "2S-10=3(S-10)<BR>\n" );
document.write( "2S-10=3S-30 Add 30 to each side.<BR>\n" );
document.write( "2S+20=3S Subtract 2S from each side.<BR>\n" );
document.write( "20=S ANSWER 1: The son is 20 years old<BR>\n" );
document.write( "F=2S=40 ANSWER 2: The father is 40 years old<BR>\n" );
document.write( "CHECK <BR>\n" );
document.write( "10 yrs ago, father was 3 times son's age:<BR>\n" );
document.write( "F-10 yrs=3(S-10 yrs)<BR>\n" );
document.write( "40 yrs-10yrs=3(20 yrs-10 yrs)<BR>\n" );
document.write( "30 yrs=3(10 yrs)<BR>\n" );
document.write( "30 yrs=30 yrs </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );