document.write( "Question 80880: Debbie traveled by boat 5 miles upstream to fish in her favorite spot. Because of the 4-mph current, it took her 20 minutes longer to get there than to return. How fast will her boat go in still water? \n" ); document.write( "
Algebra.Com's Answer #58040 by ankor@dixie-net.com(22740)\"\" \"About 
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Debbie traveled by boat 5 miles upstream to fish in her favorite spot. Because of the 4-mph current, it took her 20 minutes longer to get there than to return. How fast will her boat go in still water?
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\n" ); document.write( "let x = boat speed in still water
\n" ); document.write( "Then:
\n" ); document.write( "(x-4) = speed up-stream
\n" ); document.write( "and
\n" ); document.write( "(x+4) = speed down stream
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\n" ); document.write( "Since we are dealing in mph, change 20 min to hrs. 20/60 = 1/3 hr
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\n" ); document.write( "Write a time equation; Time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Time down-stream + 1/3 hr = time upstream
\n" ); document.write( "\"5%2F%28%28x%2B4%29%29\" + \"1%2F3\" = \"5%2F%28%28x-4%29%29\"
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\n" ); document.write( "Multiply equation by 3(x+4)(x-4) to get rid of the denominators, you then have;
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\n" ); document.write( "15(x-4) + (x+4)(x-4) = 15(x+4)
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\n" ); document.write( "15x - 60 + x^2 - 16 = 15x + 60; multiplied what's inside the brackets
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\n" ); document.write( "x^2 + 15x - 15x = + 60 + 60 + 16; x's on the left, numbers on the right
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\n" ); document.write( "x^2 = 136
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\n" ); document.write( "x = \"sqrt%28136%29\"
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\n" ); document.write( "x = 11.66 mph in still water
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "Speed up = 7.66, speed down = 15.66
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\n" ); document.write( "5/7.66 = .65 hr
\n" ); document.write( "5/15.66 = .32
\n" ); document.write( "---------------
\n" ); document.write( "subtract= .33 hr difference, check our solution of x = 11.66
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