document.write( "Question 950450: Find the area of an isosceles right triangle when the hypotenuse is 26mm. Find the area to the nearest tenth. \n" ); document.write( "
Algebra.Com's Answer #580399 by macston(5194)\"\" \"About 
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a=length 0f equal sides; h=length of hypotenuse=26mm;
\n" ); document.write( "Since a is height and base,\"area=%281%2F2%29a%5E2\"
\n" ); document.write( "\"2a%5E2=h%5E2\"
\n" ); document.write( "\"2a%5E2=%2826mm%29%5E2\"
\n" ); document.write( "\"2a%5E2=676mm%5E2\" Divide each side by 2.
\n" ); document.write( "\"a%5E2=338mm%5E2\"
\n" ); document.write( "\"Area=%281%2F2%29%28a%5E2%29\"
\n" ); document.write( "\"Area=%281%2F2%29%28338mm%5E2%29\"
\n" ); document.write( "\"Area=169mm%5E2\" ANSWER: The area is 169 sq mm. \r
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