document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=950446>Question 950446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble trying to figure out how to expand (2+(-3))^5 using the binomial theorem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #580398 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=580398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> expand (2+(-3))^5 using the binomial theorem<BR>\n" );
document.write( "------<BR>\n" );
document.write( "= 5C5(2)^5 + 5C4(2)^4(-3) + 5C3(2)^3(-3)^2 <BR>\n" );
document.write( "+ 5C2(2)^2(-3)^3 + 5C1(2)(-3)^4 + 5C0(2)^0(-3)5<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "= 32 + 5(16)(-3) + 10(8)(9) + 10(4)(-27) + 5(2)(81) + 1*1*(-243)<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );