document.write( "Question 950439: (pretend exponent ^4)
\n" ); document.write( "3. The product of two consecutive integers, n and n + 1, is 42. What is the
\n" ); document.write( "positive integer that satisfies the situation? \r
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Algebra.Com's Answer #580381 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
n(n+1)=42
\n" ); document.write( "n^2+n=42
\n" ); document.write( "n^2+n-42=0\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"an%5E2%2Bbn%2Bc=0\" (in our case \"1n%5E2%2B1n%2B-42+=+0\") has the following solutons:
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\n" ); document.write( " \"n%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-42=169\".
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\n" ); document.write( " Discriminant d=169 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+169+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"n%5B1%5D+=+%28-%281%29%2Bsqrt%28+169+%29%29%2F2%5C1+=+6\"
\n" ); document.write( " \"n%5B2%5D+=+%28-%281%29-sqrt%28+169+%29%29%2F2%5C1+=+-7\"
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\n" ); document.write( " Quadratic expression \"1n%5E2%2B1n%2B-42\" can be factored:
\n" ); document.write( " \"1n%5E2%2B1n%2B-42+=+1%28n-6%29%2A%28n--7%29\"
\n" ); document.write( " Again, the answer is: 6, -7.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-42+%29\"

\n" ); document.write( "\n" ); document.write( "The positive answer is 6.
\n" ); document.write( "ANSWER: The positive integer that satisfies the situation is 6.
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